Given that A = (2 3 / 1 -5) and B = (7 4 / 2 8), calculate 2A,
- (a)(i)Given that A = (2 3 / 1 -5) and B = (7 4 / 2 8), calculate 2A,[2]
- (a)(ii)B²,[2]
- (a)(iii)BA.[2]
- (b)(i)Given that C = (2 6 / 3 7), find C⁻¹.[2]
- (b)(ii)Given also that D = (4 3 / -2 -1), find the matrix X such that XC = D.[2]
Mark scheme
Marking points from the official mark scheme (May/June 2010). The mark or mark type is shown in brackets.
- [B1] (a)(i) (4 6 / 2 -10)
- [M1] (a)(ii) Matrix multiplication
- [A1] (a)(ii) (57 60 / 30 72)
- [M1] (a)(iii) Matrix multiplication
- [A1] (a)(iii) (18 1 / 12 -34)
- [B1+B1] (b)(i) C⁻¹ = 1/-4 (7 -6 / -3 2) or equivalent matrix
- [M1] (b)(ii) X = DC⁻¹
- [A1] (b)(ii) (0.6 0.4 / -1 0)
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