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O-LevelAdditional MathematicsDifferentiation and integration4037/12 · May/June 2017 · Q118 Marks

The curve y = f(x) passes through the point (1/2, 7/2) and is such that f'(x) = e^(2x-1).

  1. (i)Find the equation of the curve.[4]
  2. (ii)Find the value of x for which f''(x) = 4, giving your answer in the form a + b ln √2, where a and b are constants.[4]

Mark scheme

Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.

  1. [M1] me^(2x-1) where m is numeric constant
  2. [A1] f(x) = (1/2)e^(2x-1) (+c)
  3. [DM1] correct attempt to find arbitrary constant
  4. [A1] must be an equation f(x) = (1/2)e^(2x-1) + 3
  5. [M1] ke^(2x-1) where k is a numeric constant
  6. [A1] f''(x) = 2e^(2x-1)
  7. [DM1] attempt to equate to 4 and use logarithms
  8. [A1] x = 1/2 + ln√2

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About this question

Topic
Differentiation and integration, O-Level Additional Mathematics (syllabus 4037). Structured question, 8 marks.
Source
O-Level Additional Mathematics, May/June 2017 Paper 1 Variant 2, question 11.

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