Find the gradient of the curve x³ + 3xy² – y³ = 1 at the point with coordinates (1, 3).
- Find the gradient of the curve x³ + 3xy² – y³ = 1 at the point with coordinates (1, 3).[4]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [B1] State or imply 3y² + 6xy dy/dx as derivative of 3xy²
- [B1] State or imply 3y² dy/dx as derivative of y³
- [M1] Equate derivative of LHS to zero, substitute (1, 3) and find the gradient
- [A1] Obtain final answer 10/3 or equivalent
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