A particle P moves in a straight line. The velocity v m s¯¹ at time t s is given by v = 4 + 0.2t for 0 ≤ t ≤ 10, v = -2 + 800/t² for 10 ≤ t ≤ 20.
- (i)Find the acceleration of P during the first 10 s.[1]
- (ii)Find the acceleration of P when t = 20.[2]
- (iii)Sketch the velocity-time graph for 0 ≤ t ≤ 20.[3]
- (iv)Find the total distance travelled by P in the interval 0 ≤ t ≤ 20.[5]
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2018). The mark or mark type is shown in brackets.
- (i) [B1] 0.2 m s⁻²
- (ii) [M1] Attempt differentiation of v = -2 + 800t⁻² (i.e., d/dt (800t⁻²))
- (ii) [A1] a = -1600t⁻³ ; at t = 20, a = -1600 / 20³ = -0.2 m s⁻²
- (iii) [B1] Straight line joining (0,4) and (10,6)
- (iii) [B1] Curve with correct concavity (decreasing slope, becomes less negative) joining (10,6) to (20,0)
- (iii) [B1] Correct labelling on axes, showing (0,4), (10,6), (20,0)
- (iv) [B1] Distance for 0 ≤ t ≤ 10 is trapezium area: (4+6)/2 × 10 = 50 m
- (iv) [M1] Attempt integration of v = -2 + 800t⁻² with respect to t
- (iv) [A1] Correct indefinite integral: [-2t - 800t⁻¹]
- (iv) [M1] Correct use of limits for 10 ≤ t ≤ 20: [-2(20) - 800/20] - [-2(10) - 800/10] = (-40 - 40) - (-20 - 80)
- (iv) [A1] Total distance = 50 + 20 = 70 m
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