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A-LevelFurther MathematicsSummation of series9231/12 · May/June 2020 · Q410 Marks

By first expressing 1 r2-1 in partial fractions, show that n Σ r=2 1 r2-1 = 3 4 - an+b 2n(n+1) , where a and b are integers to be found.

  1. (a)By first expressing 1 r2-1 in partial fractions, show that n Σ r=2 1 r2-1 = 3 4 - an+b 2n(n+1) , where a and b are integers to be found.[5]
  2. (b)Deduce the value of ∞ Σ r=2 1 r2-1 .[1]
  3. (c)Find the limit, as n → ∞, of 2n Σ r=n+1 n r2-1 .[4]

Mark scheme

Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.

  1. [M1 A1] 1/(r²-1) = 1/((r-1)(r+1)) = 1/2 (1/(r-1) - 1/(r+1))
  2. [M1] Σ 1/(r²-1) = 1/2 [ (1/1 - 1/3) + (1/2 - 1/4) + (1/3 - 1/5) + ... + (1/(n-2) - 1/n) + (1/(n-1) - 1/(n+1)) ]
  3. [A1] = 1/2 [1 + 1/2 - 1/n - 1/(n+1)]
  4. [A1] = 3/4 - (2n+1)/(2n(n+1))
  5. [B1] 3/4
  6. [M1] Σ (from r=n+1 to 2n) n/(r²-1) = n [ Σ (from r=2 to 2n) 1/(r²-1) - Σ (from r=2 to n) 1/(r²-1) ]
  7. [M1A1] = n [ (3/4 - (4n+1)/(4n(2n+1))) - (3/4 - (2n+1)/(2n(n+1))) ]
  8. [A1] →½ as n → ∞

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About this question

Topic
Summation of series, A-Level Further Mathematics (syllabus 9231). Structured question, 10 marks.
Source
A-Level Further Mathematics, May/June 2020 Paper 1 Variant 2, question 4.

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