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A-LevelFurther MathematicsComplex numbers9231/12 · May/June 2012 · Q69 Marks

Write down the values of θ, in the interval 0 ≤ θ < 2π, for which cos θ + i sin θ is a fifth root of unity. By writing the equation (z + 1)⁵ = z⁵ in the form ((z + 1)/z)⁵ = 1, show that its roots are ½{1 + i cot(kπ/5)}, k = 1, 2, 3, 4.

  1. Write down the values of θ, in the interval 0 ≤ θ < 2π, for which cos θ + i sin θ is a fifth root of unity.[2]
  2. By writing the equation (z + 1)⁵ = z⁵ in the form ((z + 1)/z)⁵ = 1, show that its roots are ½{1 + i cot(kπ/5)}, k = 1, 2, 3, 4.[7]

Mark scheme

Marking points from the official mark scheme (May/June 2012). The mark or mark type is shown in brackets.

  1. [M1] Obtains fifth roots of unity by de M's Thm. 1 = cos(2kπ) + i sin(2kπ) k = 0, 1, 2, 3, 4.
  2. [A1] θ = 2kπ/5 k = 0, 1, 2, 3, 4.
  3. [M1] Rewrites ((z+1)/z)⁵ = 1 ⇒ z+1 = z cis(2kπ/5)
  4. [A1] and factorises. ⇒ z(1-cis(2kπ/5)) = -1
  5. [M1A1] Isolates z. z = -1/(1-cis(2kπ/5))
  6. [A1] Obtains purely imaginary denominator -(cos(kπ/5)+isin(kπ/5)) / (-2i sin(kπ/5))
  7. [A1] and obtains result. =-½{1+icot(kπ/5)} k=1,2,3,4. (AG)
  8. [B1] Observes that original equation is a quartic with real coefficients, so roots occur in conjugate pairs and k = 0 must be rejected.

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About this question

Topic
Complex numbers, A-Level Further Mathematics (syllabus 9231). Structured question, 9 marks.
Source
A-Level Further Mathematics, May/June 2012 Paper 1 Variant 2, question 6.

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