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A-LevelFurther MathematicsSummation of series9231/12 · May/June 2023 · Q37 Marks

Use the method of differences to find ∑(from r=1 to n) (1 / ((kr+1)(kr-k+1))) in terms of n and k, where k is a positive constant.

  1. (a)Use the method of differences to find ∑(from r=1 to n) (1 / ((kr+1)(kr-k+1))) in terms of n and k, where k is a positive constant.[4]
  2. (b)Deduce the value of ∑(from r=1 to ∞) (1 / ((kr+1)(kr-k+1)))[1]
  3. (c)Find also ∑(from r=n to 2n) (1 / ((kr+1)(kr-k+1))) in terms of n and k.[2]

Mark scheme

Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.

  1. M1 A1 Finds partial fractions.
  2. M1 Writes at least three complete terms, including last.
  3. A1 OE e.g. n/(kn+1)
  4. B1 1/k
  5. M1 Or applies the method of differences again.
  6. A1 OE e.g. 1/k * (1/(kn+1) - 1/(k(2n)+1))

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About this question

Topic
Summation of series, A-Level Further Mathematics (syllabus 9231). Structured question, 7 marks.
Source
A-Level Further Mathematics, May/June 2023 Paper 1 Variant 2, question 3.

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