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O-LevelAdditional MathematicsDifferentiation and integration4037/12 · May/June 2023 · Q910 Marks

The diagram shows part of the curve y = 3 + 4/(2x+1) and the straight line 3y = 2x+6. Find the area of the shaded region, giving your answer in exact form.

  1. The diagram shows part of the curve y = 3 + 4/(2x+1) and the straight line 3y = 2x+6. Find the area of the shaded region, giving your answer in exact form.[10]

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Mark scheme

Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.

  1. [M1] for equating the line and curve and obtaining a 3 term quadratic expression in terms of x. (2x+6)/3 = 3+4/(2x+1) => 4x² - 4x - 15 = 0
  2. [A1] For x-coordinate of the point of intersection. x = 5/2
  3. [M1] for attempt to integrate with one term correct ∫(3 + 4/(2x+1))dx = 3x + 2ln(2x+1)
  4. [Dep M1] for using their x-coordinate of C in their integral. Must have a term in ln(2x+1). [3x+2ln(2x+1)] evaluated.
  5. [A1] Must be exact but allow unsimplified (15/2 + 2ln6)
  6. [M1] for attempt at the trapezium, must have at least one side correct. If using integration, the integral must be correct using their 5/2. Area of trapezium = 85/12
  7. [A1] Shaded area = 2ln6 + 5/12 or ln36 + 5/12 or ln6² + 5/12

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About this question

Topic
Differentiation and integration, O-Level Additional Mathematics (syllabus 4037). Structured question, 10 marks.
Source
O-Level Additional Mathematics, May/June 2023 Paper 1 Variant 2, question 9.

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