A particle moves in a straight line such that its displacement, xm, from a fixed point O at time tseconds is given by x = 12{ln(2t+3)}. Find
- (i)the value of t when the displacement of the particle from O is 48 m,[3]
- (ii)the velocity of the particle when t = 1,[3]
- (iii)the acceleration of the particle when t=1.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2010). The mark or mark type is shown in brackets.
- M1 for attempt to deal with logs
- DM1 for attempt to solve
- A1
- B1 for 1/(2t+3)
- B1 24/(2t+3)
- B1 for 4.8
- B1 for 1/(2t+3)²
- √B1 on '24'
- B1 for -1.92
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