On the axes below sketch the graphs of y = |2x – 5| and 9y = 80x – 16x².
- (i)On the axes below sketch the graphs of y = |2x – 5| and 9y = 80x – 16x².[5]
- (ii)Solve |2x – 5|= 4.[3]
- (iii)Hence show that the graphs of y = |2x – 5| and 9y = 80x – 16x² intersect at the points where y = 4.[1]
- (iv)Hence find the values of x for which 9|2x – 5| ≤ 80x – 16x².[2]
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Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [B5] B1 for shape of modulus function
- B1 for y intercept = 5 (for modulus graph only)
- B1 for x intercept = 2.5 at the V of a modulus graph
- B1 for shape of quadratic function for -1 ≤ x ≤ 6
- B1 for intercepts at x = 0 and x = 5 for a quadratic graph
- [B1] one correct answer
- [M1] solution of two different correct linear equations or solution of an equation obtained from squaring both sides or use of symmetry from first solution.
- [A1] second correct solution x=9/2, x=1/2
- [B1] verification using both x values or for forming and solving 16x² −80x+36=0
- [M1] using their values from (ii) in an equality of the form a≤x≤b or a<x<b
- [A1] 1/2 <x< 9/2 cao
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