A car starts from rest and moves in a straight line with constant acceleration am s⁻² for a distance of 50 m. The car then travels with constant velocity for 500 m for a period of 25 s, before decelerating to rest. The magnitude of this deceleration is 2a m s⁻².
- (a)Sketch the velocity-time graph for the motion of the car.[1]
- (b)Find the value of a.[3]
- (c)Find the total time for which the car is in motion.[3]
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Mark scheme
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- [B1] Trapezium shape with gradient of right-hand side approximately 2 times left side
- [B1] Constant velocity = 500/25 = 20 ms⁻¹
- [M1] 20² = 0 + 2a × 50
- [A1] a = 4
- [B1] Time to accelerate = 20/4 = 5 s
- [B1] Deceleration time = 2.5 s
- [B1] So total time = 5 + 25 + 2.5 = 32.5 s
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