A-LevelMathematicsTrigonometry9709/22 · Feb/Mar 2019 · Q14 Marks
Solve the equation sec² θ + tan² θ = 5 tan θ + 4 for 0° < θ < 180°. Show all necessary working.
- Solve the equation sec² θ + tan² θ = 5 tan θ + 4 for 0° < θ < 180°. Show all necessary working.[4]
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2019). The mark or mark type is shown in brackets.
- [B1] Use identity sec² θ =1+ tan² θ
- [M1] Attempt solution of quadratic equation to find two values of tan
- [A1] Obtain tan θ = −½, 3
- [A1] Obtain 71.6 and 153.4 and no others between 0 and 180
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