Prove the identity sin 4x = 4 sinx(2 cos³x-cosx).
- (a)Prove the identity sin 4x = 4 sinx(2 cos³x-cosx).[3]
- (b)Hence find the exact value of ∫(from 0 to π/4) cos³ x sin 4x dx.[5]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2025). The mark or mark type is shown in brackets.
- [1] (a) Use correct double angle formula to expand sin4x (e.g., sin4x = 2sin2xcos2x).
- [1] (a) Use correct double angle formulae to obtain an expression in sin x and cos x. E.g., 2(2sinxcosx)(2cos²x−1) = 4sinxcosx(2cos²x−1).
- [1] (a) Obtain sin 4x = 4sinx(2cos³x−cosx) from fully correct working.
- [1] (b) Use the identity to obtain ∫ 8sinxcos⁶x dx - ∫ 4sinxcos⁴x dx.
- [1] (b) Obtain -8/7 cos⁷x + 4/5 cos⁵x (or r cos⁷x + s cos⁵x, or equivalent form using substitution u=cosx, -8/7 u⁷ + 4/5 u⁵).
- [1] (b) Use the correct limits correctly in an expression of the form rcos⁷x+ scos⁵x.
- [1] (b) Obtain (1/35)(√2+12). Or exact simplified equivalent (e.g. as 2 terms).
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →