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A-LevelMathematicsTrigonometry9709/12 · Feb/Mar 2021 · Q34 Marks

Solve the equation tan θ + 2 sin θ = 3 for 0° < θ < 180°. tan θ-2 sin θ

  1. Solve the equation tan θ + 2 sin θ = 3 for 0° < θ < 180°. tan θ-2 sin θ[4]

Mark scheme

Marking points from the official mark scheme (Feb/Mar 2021). The mark or mark type is shown in brackets.

  1. [1] tanθ + 2sinθ = 3tanθ – 6sinθ leading to 2tanθ – 8sinθ [= 0] (OE)
  2. [1] 2sinθ – 8sinθ cosθ [= 0] leading to [2]sinθ(1 – 4cosθ) [= 0]
  3. [1] cos θ = 1/4 (Ignore sin θ = 0)
  4. [1] θ = 75.5° only

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About this question

Topic
Trigonometry, A-Level Mathematics (syllabus 9709). Structured question, 4 marks.
Source
A-Level Mathematics, Feb/Mar 2021 Paper 1 Variant 2, question 3.

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