A-LevelMathematicsMechanics9709/42 · Feb/Mar 2020 · Q47 Marks

A cyclist travels along a straight road with constant acceleration. He passes through points A, B and C. The cyclist takes 2 seconds to travel along each of the sections AB and BC and passes through B with speed 4.5 m s⁻¹. The distance AB is 4/5 of the distance BC.

Mark scheme

Marking points from the official mark scheme (Feb/Mar 2020). The mark or mark type is shown in brackets.

[M1] Use the constant acceleration equations to obtain an expression for either sAB or sBC in terms of a
[A1] or sAB = ½(vA + vB) × 2 = 9 – 2a
[A1] or sBC = ½(vB + vC) × 2 = 9 + 2a
[M1] Use the given information to find a valid equation for a
[A1]
[M1] Attempt to find the value of sAB or sBC OR attempt to find sAB directly as sAC = 3.5 × 4 + ½ × a × 4² or ½ (4.5 – 2a + 4.5 + 2a) × 4 or add the 2 expressions found in 4(a) for sAB and sBC
[A1]

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Topic: Mechanics, A-Level Mathematics (syllabus 9709). Structured question, 7 marks.
Source: A-Level Mathematics, Feb/Mar 2020 Paper 4 Variant 2, question 4.

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