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A-LevelMathematicsTrigonometry9709/31 · May/June 2022 · Q36 Marks

Solve the equation 2 cot 2x + 3 cotx = 5, for 0° < x < 180°.

  1. Solve the equation 2 cot 2x + 3 cotx = 5, for 0° < x < 180°.[6]

Mark scheme

Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.

  1. [*M1] Use correct trigonometric formulae to form an equation in tanx e.g. 2((1-tan²x)/(2tanx)) + 3/tanx = 5
  2. [A1] Obtain a correct linear equation in any form e.g. 1 - tan²x + 3 = 5 tan x
  3. [A1] Reduce equation to a 3-term quadratic tan²x + 5 tan x − 4 = 0, or 3-term equivalent
  4. [DM1] Solve a 3-term quadratic in tan x and obtain a value of x
  5. [A1] Obtain answer, e.g. x = 35.1°
  6. [A1] Obtain second answer, e.g. x = 99.9°, and no other in (0°, 180°)
  7. Alternative method for question 3
  8. [*M1] Use correct formulae for sin2x and cos2x to form an equation in sinx and cosx
  9. [A1] Obtain 4(cosx/sinx) - (sinx/cosx) = 5
  10. [A1] Reduce equation to a 3-term quadratic tan²x + 5 tan x 4 = 0, or 3-term equivalent
  11. [DM1] Solve a 3-term quadratic in tan x and obtain a value of x
  12. [A1] Obtain answer, e.g. x = 35.1°
  13. [A1] Obtain second answer, e.g. x = 99.9°, and no other in (0°,180°)

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About this question

Topic
Trigonometry, A-Level Mathematics (syllabus 9709). Structured question, 6 marks.
Source
A-Level Mathematics, May/June 2022 Paper 3 Variant 1, question 3.

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