The polynomial p(x) is defined by p(x) = ax³ + bx² – 17x – a, where a and b are constants. It is given that (x + 2) is a factor of p(x) and that the remainder is 28 when p(x) is divided by (x – 2).
- (i)Find the values of a and b.[5]
- (ii)Hence factorise p(x) completely.[3]
- (iii)State the number of roots of the equation p(2ˣ) = 0, justifying your answer.[2]
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2017). The mark or mark type is shown in brackets.
- [M1] Substitute x = −2 and equate to zero
- [M1] Substitute x = 2 and equate to 28
- [A1] Obtain −9a + 4b + 34 = 0 and 7a + 4b – 62 = 0 or equivalents
- [M1] Solve a relevant pair of simultaneous equations for a or b
- [A1] Obtain a = 6, b = 5
- [M1] Divide by x + 2, or equivalent, at least as far as k₁x² + k₂x
- [A1] Obtain 6x² – 7x – 3
- [A1] Obtain (x + 2)(3x + 1)(2x – 3)
- [M1] Refer to, or clearly imply, fact that 2ˣ is positive
- [A1] State one
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →