Given that Uk = 1/√(2k-1) - 1/√(2k+1), express ∑(from k=1 to n) Uk in terms of n. Deduce the value of ∑(from k=1 to ∞) Uk
- mainGiven that Uk = 1/√(2k-1) - 1/√(2k+1), express ∑(from k=1 to n) Uk in terms of n. Deduce the value of ∑(from k=1 to ∞) Uk[5]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2014). The mark or mark type is shown in brackets.
- [M1A1] (1/√1 - 1/√3) + (1/√3 - 1/√5) + ... + (1/√(2n-1) - 1/√(2n+1))
- [M1A1] = 1 - 1/√(2n+1)
- [B1] 1
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