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A-LevelFurther MathematicsMatrices9231/12 · May/June 2013 · Q69 Marks

The matrix A is given by A = [[4, -5, 3], [3, -4, 3], [1, -1, 2]] Show that e = [[1], [1], [1]] is an eigenvector of A and state the corresponding eigenvalue. Find the other two eigenvalues of A. The matrix B is given by B = [[-1, 4, 0], [-1, 3, 1], [1, -1, 3]] Show that e is an eigenvector of B and deduce an eigenvector of the matrix AB, stating the corresponding eigenvalue.

  1. (a)The matrix A is given by A = [[4, -5, 3], [3, -4, 3], [1, -1, 2]] Show that e = [[1], [1], [1]] is an eigenvector of A and state the corresponding eigenvalue.[2]
  2. (b)Find the other two eigenvalues of A.[4]
  3. (c)The matrix B is given by B = [[-1, 4, 0], [-1, 3, 1], [1, -1, 3]] Show that e is an eigenvector of B and deduce an eigenvector of the matrix AB, stating the corresponding eigenvalue.[3]

Mark scheme

Marking points from the official mark scheme (May/June 2013). The mark or mark type is shown in brackets.

  1. M1A1 Shows e is an eigenvector of A and gives eigenvalue. Ae = 2e ⇒ e is an eigenvector with eigenvalue 2.
  2. M1A1 Finds characteristic equation. λ³ – 2λ² – λ + 2 = 0
  3. A1 Factorises. ⇒ (λ – 2)(λ² – 1) = 0
  4. A1 States other eigenvalues. Other eigenvalues are -1 and 1.
  5. B1 Repeats for B. Be = 3e ⇒ e is an eigenvector with eigenvalue 3
  6. M1A1 States result for AB. ABe = A.3e = 3Ae = 3.2e = 6e. AB has eigenvector e with eigenvalue 6

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About this question

Topic
Matrices, A-Level Further Mathematics (syllabus 9231). Structured question, 9 marks.
Source
A-Level Further Mathematics, May/June 2013 Paper 1 Variant 2, question 6.

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