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O-LevelAdditional MathematicsTrigonometry4037/12 · Oct/Nov 2017 · Q1111 Marks

Solve 2 cot(φ + 35°) = 5 for 0° ≤ φ ≤ 360°.

  1. (a)Solve 2 cot(φ + 35°) = 5 for 0° ≤ φ ≤ 360°.[4]
  2. (b)(i)Show that sec θ / (cot θ + tan θ) = sin θ.[3]
  3. (b)(ii)Hence solve sec 3θ / (cot 3θ + tan 3θ) = √3 / 2 for -π/2 ≤ θ ≤ π/2, giving your answers in terms of π.[4]

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About this question

Topic
Trigonometry, O-Level Additional Mathematics (syllabus 4037). Structured question, 11 marks.
Source
O-Level Additional Mathematics, Oct/Nov 2017 Paper 1 Variant 2, question 11.

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