Prove that 1/(1 - sinx) - 1/(1 + sinx) = 2 tanx secx.
- (a)Prove that 1/(1 - sinx) - 1/(1 + sinx) = 2 tanx secx.[3]
- (b)An acute angle x is such that sinx = p. Given that sin 2x = 2sinx cosx, find an expression, in terms of p, for cosec 2x.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2011). The mark or mark type is shown in brackets.
- [1] (a) Expresses with common denominator: (1+sinx) - (1-sinx) / (1-sinx)(1+sinx)
- [1] (a) = 2 sin x / cos² x
- [1] (a) = 2 (sin x / cos x) (1 / cos x) = 2 tan x sec x (AG)
- [1] (b) cos x = √(1 - p²)
- [1] (b) cosec 2x = 1 / sin 2x
- [1] (b) = 1 / (2p√(1 - p²))
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