O-LevelAdditional MathematicsTrigonometry4037/21 · May/June 2011 · Q1013 Marks
Solve the equation 3 sinx + 4 cosx = 0 for 0° < x < 360°.
- (i)Solve the equation 3 sinx + 4 cosx = 0 for 0° < x < 360°.[5]
- (ii)Solve the equation 6 cosy + 6 secy = 13 for 0° < y < 360°.[5]
- (iii)Solve the equation sin(2z – 3) = 0.7 for 0 < z < π radians.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2011). The mark or mark type is shown in brackets.
- [1] (i) tanx = -4/3
- [1] (i) Reference angle 53.1°
- [1] (i) x = 126.9°
- [1] (i) x = 306.9°
- [1] (i) Correct steps to obtain the angles
- [1] (ii) 6 cosy + 6/cosy = 13
- [1] (ii) Forms quadratic in cosy (6cos²y – 13cosy + 6 = 0)
- [1] (ii) Solve 3 term quadratic
- [1] (ii) 48.2°
- [1] (ii) 311.8°
- [1] (iii) 2z-3 = 0.775 (principal value of arcsin(0.7))
- [1] (iii) 2z-3 = π - 0.775 = 2.366 (second value)
- [1] (iii) 1.89 and 2.68
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