A function f is defined by f : x → 18 + 16x – 2x² for x ∈ R.
- (a)(i)Express 18 + 16x – 2x² in the form a + b(x + c)², where a, b and c are integers.[3]
- (a)(ii)Write down the coordinates of the stationary point on the graph of y = f(x).[1]
- (a)(iii)Sketch the graph of y = f(x).[2]
- (b)(i)A function g is defined by g : x → (x + 3)² – 7 for x > −3. Find an expression for g⁻¹(x).[2]
- (b)(ii)Solve the equation g⁻¹(x) = g(0).[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2011). The mark or mark type is shown in brackets.
- [1] (a)(i) a = 50
- [1] (a)(i) b = -2 OR 50-2(x-4)²
- [1] (a)(i) c = -4
- [1] (a)(ii) (4, 50)
- [1] (a)(iii) Correct shape (inverted parabola)
- [1] (a)(iii) Maximum and y intercept in correct quadrant (Maximum at (4,50), y-intercept at (0,18))
- [1] (b)(i) Method for inverse (e.g., y=(x+3)²-7 => x+3=√(y+7) => x=√(y+7)-3)
- [1] (b)(i) √(x+7)-3
- [1] (b)(ii) g(0) = 2
- [1] (b)(ii) Solves g⁻¹(x) = 2 or solves x = g(g(0)) = g(2)
- [1] (b)(ii) 18
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →