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O-LevelAdditional MathematicsFunctions4037/11 · May/June 2016 · Q69 Marks

The function f is defined by f(x) = 2 - √x+5 for -5 ≤ x < 0.

  1. (i)Write down the range of f.[2]
  2. (ii)Find f⁻¹(x) and state its domain and range.[4]
  3. (iii)Solve fg(x) = 0 .[3]

Mark scheme

Marking points from the official mark scheme (May/June 2016). The mark or mark type is shown in brackets.

  1. [1] f(x) < 2
  2. [1] 2 - √5 < f(x)
  3. [1] f⁻¹(x) = (2-x)² - 5
  4. [1] f⁻¹(x) = (2-x)² - 5
  5. [1] Domain 2 - √5 < x < 2
  6. [1] Range y or -5 < f⁻¹(x) < 0
  7. [1] fg(x) = f(4/x)
  8. [1] = 2 - √(4/x + 5)
  9. [1] x = -4

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About this question

Topic
Functions, O-Level Additional Mathematics (syllabus 4037). Structured question, 9 marks.
Source
O-Level Additional Mathematics, May/June 2016 Paper 1 Variant 1, question 6.

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