The variables x and y are such that when lny is plotted against x, a straight line graph is obtained. This line passes through the points x = 4, lny = 0.20 and x = 12, lny = 0.08.
- (i)Given that y = Abˣ, find the value of A and of b.[5]
- (ii)Find the value of y when x = 6 .[2]
- (iii)Find the value of x when y = 1.1 .[2]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2016). The mark or mark type is shown in brackets.
- [1] (i) ln y = ln A + x ln b B1 may be implied, if equation not seen specifically, by correct values for A and b
- [1] (i) Gradient: ln b = (0.08 - 0.20) / (12 - 4) = -0.12 / 8 = -0.015 M1 for use of gradient to obtain ln b
- [1] (i) b = 0.985 A1 Allow A1 for e⁻⁰·⁰¹⁵
- [1] (i) Intercept: ln A = 0.26 DM1 for use of one of the given points correctly
- [1] (i) A = 1.30 A1 Allow A1 for e⁰·²⁶ or 1.3
- [1] (ii) When x = 6, ln y = ln A + 6 ln b M1 for ln y = their ln A + 6 their ln b or y = their A × (their b)⁶
- [1] (ii) y = 1.19 A1 allow awrt 1.18 to 1.20
- [1] (iii) When y=1.1, ln y = 0.095 M1 for ln 1.1 = their ln A + x their ln b or 1.1 = their A × (their b)ˣ
- [1] (iii) x = 11 A1 allow 10.5 to 11.5
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