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O-LevelAdditional MathematicsStraight line graphs4037/11 · May/June 2018 · Q25 Marks

Find the equation of the perpendicular bisector of the line joining the points (1, 3) and (4, −5). Give your answer in the form ax + by + c = 0, where a, b and c are integers.

  1. Find the equation of the perpendicular bisector of the line joining the points (1, 3) and (4, −5). Give your answer in the form ax + by + c = 0, where a, b and c are integers.[5]

Mark scheme

Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.

  1. [B1] Midpoint (5/2, -1)
  2. [B1] Gradient of line -8/3
  3. [M1] Gradient of perp = 3/8
  4. [M1] M1 dep Using their perpendicular gradient and their midpoint
  5. [A1] 6x-16y-31=0 or -6x+16y+31=0

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About this question

Topic
Straight line graphs, O-Level Additional Mathematics (syllabus 4037). Structured question, 5 marks.
Source
O-Level Additional Mathematics, May/June 2018 Paper 1 Variant 1, question 2.

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