The variables x and y are such that when eʸ is plotted against x², a straight line graph passing through the points (5, 3) and (3, 1) is obtained. Find y in terms of x.
- The variables x and y are such that when eʸ is plotted against x², a straight line graph passing through the points (5, 3) and (3, 1) is obtained. Find y in terms of x.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.
- B1 eʸ = ax² + b may be implied, b≠ 0
- M1 correct attempt to find a or b by use of simultaneous equations or finding the gradient and equating it to a either 3=5a+b 1=3a+b or Gradient = 1, so a = 1
- A1 Coefficient of x² is 1
- A1 Intercept is -2
- A1 For correct form y = ln(x² - 2)
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