Find the equation of the normal to the curve y = (1/2)ln(3x + 2) at the point P where x = -1/3.
- (i)Find the equation of the normal to the curve y = (1/2)ln(3x + 2) at the point P where x = -1/3.[4]
- (ii)The normal to the curve at the point P intersects the y-axis at the point Q. The curve y = (1/2)ln(3x + 2) intersects the y-axis at the point R . Find the area of the triangle PQR.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2016). The mark or mark type is shown in brackets.
- [1] (i) dy/dx = 3/(2(3x+2)) B1 for correct derivative of log function
- [1] (i) When x = -1/3, y = 0, dy/dx = 3/2 B1 for y = 0
- [2] (i) Equation of normal: y = -2/3 (x + 1/3) M1 A1 M1 for attempt at a gradient of a perpendicular from differentiation and the equation of the normal
- [1] (ii) Q(0, -2/9) or (0, -0.22) or better B1 ft Follow through on their c from part (i)
- [1] (ii) R(0, 1/2 ln 2) or (0, 0.35) or better B1
- [1] (ii) Area of PQR = 1/2 × (1/2 ln 2 + 2/9) × 1/3 = 0.0948 B1 Allow 0.095
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →