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O-LevelAdditional MathematicsPermutations and combinations4037/12 · Oct/Nov 2013 · Q77 Marks

Find how many different 4-digit numbers can be formed from the digits 1, 3, 5, 6, 8 and 9 if each digit may be used only once.

  1. (a)(i)Find how many different 4-digit numbers can be formed from the digits 1, 3, 5, 6, 8 and 9 if each digit may be used only once.[1]
  2. (a)(ii)Find how many of these 4-digit numbers are even.[1]
  3. (b)A team of 6 people is to be selected from 8 men and 4 women. Find the number of different teams that can be selected if
  4. (b)(i)there are no restrictions,[1]
  5. (b)(ii)the team contains all 4 women,[1]
  6. (b)(iii)the team contains at least 4 men.[3]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2013). The mark or mark type is shown in brackets.

  1. [B1] (a) (i) 360
  2. [B1] (a) (ii) 120
  3. [B1] (b) (i) 924
  4. [B1] (b) (ii) 28
  5. [M1] (b) (iii) for 3 terms, at least 2 of which must be correct in terms of C notation or evaluated. (e.g. 924 -(⁸C₃ × ⁴C₃)-(⁸C₂ × ⁴C₄))
  6. [A1] for any pair (must be evaluated)
  7. [A1] for final answer (672)
  8. Or:
  9. [M1] for 3 terms, at least 2 of which must be correct in terms of C notation or evaluated. (e.g. ⁸C₄ × ⁴C₂ + ⁸C₅ × ⁴C₁ + ⁸C₆)
  10. [A1] for any pair (must be evaluated)
  11. [A1] for final answer (672)

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About this question

Topic
Permutations and combinations, O-Level Additional Mathematics (syllabus 4037). Structured question, 7 marks.
Source
O-Level Additional Mathematics, Oct/Nov 2013 Paper 1 Variant 2, question 7.

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