How many different 5-digit numbers can be formed using the digits 1, 2, 4, 5, 7 and 9 if no digit is repeated?
- (a)(i)How many different 5-digit numbers can be formed using the digits 1, 2, 4, 5, 7 and 9 if no digit is repeated?[1]
- (a)(ii)How many of these numbers are even?[1]
- (a)(iii)How many of these numbers are less than 60000 and even?[3]
- (b)How many different groups of 6 children can be chosen from a class of 18 children if the class contains one set of twins who must not be separated?[3]
Mark scheme
Marking points from the official mark scheme (May/June 2014). The mark or mark type is shown in brackets.
- [B1] (a)(i) 720
- [B1] (a)(ii) 240
- [B1] (a)(iii) Starts with either a 2 or a 4: 48 ways
- [B1] (a)(iii) Does not start with either a 2 or a 4: 96 ways (i.e. starts with 1 or 5)
- [B1] (a)(iii) Total = 144
- [B1] (a)(iii) Ends with a 2, starts with a 1,4 or 5 : 72 ways
- [B1] (a)(iii) Ends with a 4, starts with a 1,2 or 5 : 72 ways
- [B1] (a)(iii) Total =144
- [B2] (a)(iii) B2 for correct expression seen, allow P notation
- [B1] (a)(iii) Allow P notation here, for B2
- [B1] (b) With twins: ⁱ⁶C₄ (=1820)
- [B1] (b) Without twins: ⁱ⁶C₆ (= 8008)
- [B1] (b) Total: 9828
- [B1,B1] (b) B1 for ⁱ⁸C₆ -....,, B1 for 2×ⁱ⁶C₅
- [B1] (b) = 9828
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