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O-LevelAdditional MathematicsPermutations and combinations4037/12 · May/June 2014 · Q88 Marks

How many different 5-digit numbers can be formed using the digits 1, 2, 4, 5, 7 and 9 if no digit is repeated?

  1. (a)(i)How many different 5-digit numbers can be formed using the digits 1, 2, 4, 5, 7 and 9 if no digit is repeated?[1]
  2. (a)(ii)How many of these numbers are even?[1]
  3. (a)(iii)How many of these numbers are less than 60000 and even?[3]
  4. (b)How many different groups of 6 children can be chosen from a class of 18 children if the class contains one set of twins who must not be separated?[3]

Mark scheme

Marking points from the official mark scheme (May/June 2014). The mark or mark type is shown in brackets.

  1. [B1] (a)(i) 720
  2. [B1] (a)(ii) 240
  3. [B1] (a)(iii) Starts with either a 2 or a 4: 48 ways
  4. [B1] (a)(iii) Does not start with either a 2 or a 4: 96 ways (i.e. starts with 1 or 5)
  5. [B1] (a)(iii) Total = 144
  6. [B1] (a)(iii) Ends with a 2, starts with a 1,4 or 5 : 72 ways
  7. [B1] (a)(iii) Ends with a 4, starts with a 1,2 or 5 : 72 ways
  8. [B1] (a)(iii) Total =144
  9. [B2] (a)(iii) B2 for correct expression seen, allow P notation
  10. [B1] (a)(iii) Allow P notation here, for B2
  11. [B1] (b) With twins: ⁱ⁶C₄ (=1820)
  12. [B1] (b) Without twins: ⁱ⁶C₆ (= 8008)
  13. [B1] (b) Total: 9828
  14. [B1,B1] (b) B1 for ⁱ⁸C₆ -....,, B1 for 2×ⁱ⁶C₅
  15. [B1] (b) = 9828

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About this question

Topic
Permutations and combinations, O-Level Additional Mathematics (syllabus 4037). Structured question, 8 marks.
Source
O-Level Additional Mathematics, May/June 2014 Paper 1 Variant 2, question 8.

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