The diagram shows part of the curve y = x³ – 9x² + 24x + 2 cutting the y-axis at the point P. The curve has a minimum point at Q. [Figure 10.1]
- (i)Find the coordinates of the point Q.[4]
- (ii)Find the area of the region enclosed by the curve and the line PQ.[6]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2011). The mark or mark type is shown in brackets.
- [B1] (i) 3x² - 18x + 24
- [M1] (i) Solves 3 term quadratic equals zero
- [A1 cso] (i) x = 4 (and x = 2)
- [A1] (i) Q(4, 18)
- [B2, 1, 0] (ii) x⁴/4 - 3x³ + 12x² + 2x
- [M1] (ii) Uses limits of 0 and xQ in integral (area under curve = 72)
- [B1] (ii) Area under PQ = (32 + 8)
- [M1] (ii) Plan for area including use of limits
- [A1] (ii) 32
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