The coefficient of x² in the expansion of (1 + x/5)ⁿ, where n is a positive integer, is 3/5.
- (i)Find the value of n.[4]
- (ii)Using this value of n, find the term independent of x in the expansion of (1 + x/5)ⁿ (2 - 3/x)².[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2011). The mark or mark type is shown in brackets.
- [1] (i) n(n-1)/(2*25)
- [1] (i) n(n-1)/(2*25) = 3/5
- [1] (i) n² - n - 30 = 0
- [1] (i) n = 6
- [1] (ii) B1 for 4
- [1] (ii) M1 for 2nd term (-72/5 or -14.4)
- [1] (ii) M1 for 3rd term (27/5 or 5.4)
- [1] (ii) = -5
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