The first 3 terms in the expansion of (3 - x/6)^n are 81 + ax + bx². Find the value of each of the constants n, a and b.
- The first 3 terms in the expansion of (3 - x/6)^n are 81 + ax + bx². Find the value of each of the constants n, a and b.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [B1] 3^n = 81, so n=4
- [M1] for -n3^(n-1)(x/6), "C13^(n-1)(x/6)" with/without their n
- [A1] using their n and equating to a to obtain a=-18
- [M1] for n(n-1)/2 * 3^(n-2) * (x/6)², "C23^(n-2)(x/6)²" with/without their n
- [A1] using their n and equating to b to obtain b=3/2
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →