The line y = 3x-2 intersects the curve 2x²-xy+y² = 2 at the points A and B. The point C with coordinates (k, 7/8) lies on the perpendicular bisector of the line AB. Find the exact value of k.
- (a)The line y = 3x-2 intersects the curve 2x²-xy+y² = 2 at the points A and B. The point C with coordinates (k, 7/8) lies on the perpendicular bisector of the line AB. Find the exact value of k.[9]
- (b)The point D lies on the perpendicular bisector of AB such that D is a reflection of C in the line AB. Find the coordinates of D.[2]
Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [M1] 2x²-x(3x-2)+(3x-2)² = 2 or 2( (y+2)/3 )² - y( (y+2)/3 ) + y² = 2 For a quadratic equation in one variable
- [A1] 4x²-5x+1=0 oe or 4y² + y-5=0 oe Allow multiples but must be a 3 term equation = 0
- [A1] x = 1/4, x = 1
- [A1] y = -5/4, y = 1
- [M1] Midpoint: (5/8, 1/8) Allow for use of their coordinates
- [M1] Gradient of AB = 3 Allow for use of their coordinates
- [M1] Perpendicular gradient: -1/3 Dep on previous M mark
- [M1] Perpendicular equation: y+5/8 = -1/3 (x-1/8) Allow for their perp gradient and their midpoint
- [A1] k = 19/8 or -2.375 oe
- [B1] x-coordinate: 29/8 or 3.625 oe
- [B1] y-coordinate: 9/8 or 1.125 oe
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