O-LevelAdditional MathematicsTrigonometry4037/11 · May/June 2024 · Q85 Marks
8 Solve the equation 4 sin²(2α-π/3) = 1 for -π/2 < α < π/2. Give your answers in terms of π.
- Solve the equation 4 sin²(2α-π/3) = 1 for -π/2 < α < π/2. Give your answers in terms of π.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [5] B1 Condone if ± is missing for this mark (sin(2α-π/3) = ±1/2)
- [5] M1 for correct attempt to obtain one solution using correct order of operations
- [5] A3 for 4 correct solutions and no extras in the range, or A2 for 3 correct solutions or A1 for 2 correct solutions (α = 5π/12, π/4, -π/12, -π/4 oe in terms of π)
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