Variables x and y are such that, when lg(2y+1) is plotted against x², a straight line graph passing through the points (1, 1) and (2, 5) is obtained.
- (a)Find y in terms of x.[4]
- (b)Find the value of y when x = √3/2 .[1]
- (c)Find the value of x when y = 2.[2]
Mark scheme
Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.
- [B1] Gradient = 4 soi
- [B1] Intercept = -3 soi
- [M1] For lg(2y +1)= their m(x²)+ their c
- [A1] y = (10^(4x²-3) - 1)/2 or y = (10^(4x²)/1000 - 1)/2
- [B1] y = 0 (Must have at least 3 marks from part (a))
- [M1 Dep on M mark in part (a)] for use of y = 2 in their y = 1/2 (10^(4x²-3)-1)
- [A1] x = (±) 0.962 or better
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →