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O-LevelAdditional MathematicsFunctions4037/11 · May/June 2022 · Q310 Marks

A function f is such that f(x) = ln (2x+1), for x > -1/2. A function g is such that g(x) = 5x-7, for x ∈ R.

  1. (a)Write down the range of f.[1]
  2. (b)Find the exact solution of the equation gf(x) = 13.[3]
  3. (c)Find the solution of the equation f'(x) = g⁻¹(x).[6]

Mark scheme

Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.

  1. [1] B1 Must be using correct notation, allow y ∈ (for f(x) ∈ R oe)
  2. [3] M1 For correct order (for 5(ln(3x + 1)) - 7 = 13)
  3. M1 for a correct attempt to solve to get x =, allow one sign error
  4. Dep on previous M mark
  5. A1 all correct must be exact (for x = (e^4 - 1)/2)
  6. [6] M1 for a/(2x+1) (for (f'(x) =) 2/(2x+1))
  7. A1 all correct
  8. B1 soi (for (g⁻¹(x) =) (x+7)/5)
  9. M1 for equating and forming a 3-term quadratic equation = 0 (for 2x² + 15x - 3 = 0)
  10. M1 For solution of their 3-term quadratic (for x = 0.195, -7.69)
  11. A1 For discounting negative root. (for x = 0.195)

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About this question

Topic
Functions, O-Level Additional Mathematics (syllabus 4037). Structured question, 10 marks.
Source
O-Level Additional Mathematics, May/June 2022 Paper 1 Variant 1, question 3.

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