A function f is such that f(x) = ln (2x+1), for x > -1/2. A function g is such that g(x) = 5x-7, for x ∈ R.
- (a)Write down the range of f.[1]
- (b)Find the exact solution of the equation gf(x) = 13.[3]
- (c)Find the solution of the equation f'(x) = g⁻¹(x).[6]
Mark scheme
Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.
- [1] B1 Must be using correct notation, allow y ∈ (for f(x) ∈ R oe)
- [3] M1 For correct order (for 5(ln(3x + 1)) - 7 = 13)
- M1 for a correct attempt to solve to get x =, allow one sign error
- Dep on previous M mark
- A1 all correct must be exact (for x = (e^4 - 1)/2)
- [6] M1 for a/(2x+1) (for (f'(x) =) 2/(2x+1))
- A1 all correct
- B1 soi (for (g⁻¹(x) =) (x+7)/5)
- M1 for equating and forming a 3-term quadratic equation = 0 (for 2x² + 15x - 3 = 0)
- M1 For solution of their 3-term quadratic (for x = 0.195, -7.69)
- A1 For discounting negative root. (for x = 0.195)
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →