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O-LevelAdditional MathematicsStraight line graphs4037/12 · May/June 2019 · Q89 Marks

When eʸ is plotted against 1/x, a straight line graph passing through the points (2, 20) and (4, 8) is obtained.

  1. (i)Find y in terms of x.[5]
  2. (ii)Hence find the positive values of x for which y is defined.[1]
  3. (iii)Find the exact value of y when x = 3.[1]
  4. (iv)Find the exact value of x when y = 2.[2]

Mark scheme

Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.

  1. [B1] eʸ = m/x + c May be implied by subsequent work
  2. [M1] Either 20 = 2m + c 8 = 4m + c For at least 1 correct equation
  3. [M1] Dep For attempt to solve their 2 equations simultaneously to obtain at least one unknown
  4. [A1] leading to m=-6, c=32 For both
  5. [A1] y = ln (32 - 6/x) Must have correct brackets Mark the final answer given
  6. [M1] Or: Gradient = m = (-6) For attempt to find gradient and equate it to m
  7. [M1] 20 = 2m + c or 8 = 4m + c or eʸ-8=m(1/x - 4) or eʸ-20=m(1/x - 2) For at least 1 correct equation, may be using their m
  8. [A1] leading to c = 32 and m = -6 For both m=-6, c=32
  9. [A1] y = ln (32 - 6/x)
  10. [B1] x > 3/16 oe
  11. [B1] y = ln 30 isw
  12. [M1] 2 = ln(32 - 6/x) For a correct substitution and attempt to re-arrange using 2, their 32 and their – 6, keeping exactness to obtain x =
  13. [A1] x = 6/(32-e²) oe Must be exact

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About this question

Topic
Straight line graphs, O-Level Additional Mathematics (syllabus 4037). Structured question, 9 marks.
Source
O-Level Additional Mathematics, May/June 2019 Paper 1 Variant 2, question 8.

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