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O-LevelAdditional MathematicsSeries4037/22 · May/June 2020 · Q1011 Marks

10 (a) The first 5 terms of a sequence are given below. 4 -2 1 -0.5 0.25

  1. (a)(i)Find the 20th term of the sequence.[2]
  2. (a)(ii)Explain why the sum to infinity exists for this sequence and find the value of this sum.[2]
  3. (b)(i)The tenth term of an arithmetic progression is 15 times the second term. The sum of the first 6 terms of the progression is 87. Find the common difference of the progression.[4]
  4. (b)(ii)For this progression, the nth term is 6990. Find the value of n.[3]

Mark scheme

Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.

  1. [1] (a)(i) 4×(-0.5)^19
  2. [1] (a)(i) -1/131072 or -7.63×10^-6 or -7.62939...×10^-6 rot to four or more figs
  3. [1] (a)(ii) Valid explanation e.g. the common ratio is between -1 and 1
  4. [1] (a)(ii) 4/(1-(-0.5)) = 8/3
  5. [1] (b)(i) a+9d=15(a+d)
  6. [1] (b)(i) 6/2 {2a+5d} = 87
  7. [1] (b)(i) Solves their equations for d e.g. 2(-3/7 d) + 5d = 29
  8. [1] (b)(i) d=7
  9. [1] (b)(ii) a = -3 soi
  10. [1] (b)(ii) 6990 = their(-3)+(n-1)(their7)
  11. [1] (b)(ii) n = 1000

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About this question

Topic
Series, O-Level Additional Mathematics (syllabus 4037). Structured question, 11 marks.
Source
O-Level Additional Mathematics, May/June 2020 Paper 2 Variant 2, question 10.

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