O-LevelAdditional MathematicsStraight line graphs4037/22 · May/June 2013 · Q88 Marks
Solutions to this question by accurate drawing will not be accepted. The points A(-6, 2), B(2, 6) and C are the vertices of a triangle.
- (i)Find the equation of the line AB in the form y = mx + c.[2]
- (ii)Given that angle ABC = 90°, find the equation of BC.[2]
- (iii)Given that the length of AC is 10 units, find the coordinates of each of the two possible positions of point C.[4]
Mark scheme
Marking points from the official mark scheme (May/June 2013). The mark or mark type is shown in brackets.
- [M1] (i) y - 2 = ((6-2)/(2-(-6)))(x+6) o.e. soi
- [A1] (i) y = (1/2)x + 5 isw
- [M1] (ii) Use of m₁m₂ = -1
- [A1 FT] (ii) y - 6 = (their –2)(x – 2) or better, isw
- [B1] (iii) (x + 6)² + (y − 2)² = 10² o.e.
- [M1*] (iii) Substitute y = their (−2x + 10)
- [M1 dep*] (iii) Solve their quadratic
- [A1] (iii) (0, 10) and (4, 2) o.e. only
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →