[Figure 11.1] The diagram shows a cuboid of height h units inside a right pyramid OPQRS of height 8 units and with square base of side 4 units. The base of the cuboid sits on the square base PQRS of the pyramid. The points A, B, C and D are corners of the cuboid and lie on the edges OP, OQ, OR and OS, respectively, of the pyramid OPQRS. The pyramids OPQRS and OABCD are similar.
- (i)Find an expression for AD in terms of h and hence show that the volume V of the cuboid is given by V = (h³/4) - 4h² + 16h units³.[4]
- (ii)Given that h can vary, find the value of h for which V is a maximum.[4]
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Mark scheme
Marking points from the official mark scheme (May/June 2015). The mark or mark type is shown in brackets.
- [M1] (8-h)/8 = AD/4 or 8-h : 8 or 8-h : 8-h soi
- [A1] AD = 4(8-h)/8 oe or 4(1-h/8) or 4 - h/2 oe
- [M1] h x ( (8-h)/8 x 4)² oe h must be in the numerator of the expression for this mark;
- [A1] expand and simplify to h³/4 - 4h² + 16h AG
- [B1] their h²/4 - 8h + 16 oe
- [M1] their (h²/4 - 8h + 16) = 0 and attempt to solve must be a 3-term quadratic; must be an attempt at a derivative
- [A2] h = 8/3 oe only or A1 for h = 8/3 and 8
- allow 2.67 or 2.66(6...) rot to 4 or more figs for 8/3
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