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O-LevelAdditional MathematicsDifferentiation and integration4037/22 · May/June 2014 · Q99 Marks

A curve is such that dy/dx = (2x + 1)². The curve passes through the point (4, 10).

  1. (i)Find the equation of the curve.[4]
  2. (ii)Find ∫ydx and hence evaluate ∫(from 0 to 1.5) ydx.[5]

Mark scheme

Marking points from the official mark scheme (May/June 2014). The mark or mark type is shown in brackets.

  1. [B2] [=] (2x+1)³ / (2×3) (+ c) oe or B1 for (2x+1)³/(..) (+c)
  2. [M1] 10 = (2(4)+1)³ / 6 + c oe for valid attempt to find c; condone slips e.g. omission of power or sign error
  3. [A1] y = (2x+1)³ / 6 + 1 isw must have y = ....; condone f(x) = ..
  4. [B1 + B1] ∫((2x+1)³/6 + 1)dx = (2x+1)⁴ / (15) + x (+ const) B1 for (2x+1)⁴ / 15, B1 for + x
  5. [B1ft] B1 ft their c from (i) provided c≠0
  6. [M1] for a genuine attempt to find F(1.5) – F(0) in an attempt to integrate their y; if their F(0) is 0 must see at least their F(1.5)– 0; condone + c as long as their c is not numerical.
  7. [A1] 107/30 oe isw if decimal 3.57 or more accurate e.g. 3.566

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About this question

Topic
Differentiation and integration, O-Level Additional Mathematics (syllabus 4037). Structured question, 9 marks.
Source
O-Level Additional Mathematics, May/June 2014 Paper 2 Variant 2, question 9.

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