Solutions to this question by accurate drawing will not be accepted. The points A and B have coordinates (p, 3) and (1, 4) respectively and the line L has equation 3x+y = 2.
- (i)Given that the gradient of AB is 1/3, find the value of p.[2]
- (ii)Show that L is the perpendicular bisector of AB.[3]
- (iii)Given that C(q, – 10) lies on L, find the value of q.[1]
- (iv)Find the area of triangle ABC.[2]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [M1] (4-3) / (1-p) = 1/3 oe (ALT uses y=mx+c with A and B as far as an equation in p only)
- [A1] -2
- [B1] FT their p. Finds midpoint AB ((their p+1)/2, (3+4)/2)
- [B1] Verifies (-0.5,3.5) is on L
- [B1] y = -3x+2 therefore m = -3 oe AND (1/3) * (-3) = -1 oe
- [B1] q = 4
- [B2] 22.5 nfww (B1 for correct method to find area using correct values e.g. 1/2 * AB * MC where M is the midpoint of AB)
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