The first three terms of an arithmetic progression are lgx, lgx³, lgx⁹, where x > 0.
- (a)Show that the sum to n terms of this arithmetic progression can be written as n(pn-1)lgx, where p is an integer.[4]
- (b)Hence find the value of n for which the sum to n terms is equal to 4950lgx.[2]
- (c)Given that this sum to n terms is also equal to -14850, find the exact value of x.[2]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2022). The mark or mark type is shown in brackets.
- [1] (a) Common difference = 4lgx
- [1] (a) For use of the sum formula S_n = n/2 (2a + (n-1)d) with their common difference
- [1] (a) For a correct attempt to rearrange to the required form n(2n-1)lgx
- [1] (a) Final answer n(2n-1)lgx shown correctly (AG)
- [1] (b) For n((their p)n-1)=4950 together with an attempt to solve to obtain n
- [1] (b) n = 50 (cao)
- [1] (c) For use of their n and p in a complete method to find x or use of part (b)
- [1] (c) x = 10⁻³ or equivalent
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