A pendulum consists of a metal sphere P suspended from a fixed point by means of a thread, as illustrated in Fig. 3.1. [Figure 3.1]. The centre of gravity of sphere P is a distance L from the fixed point. The sphere is pulled to one side and then released so that it oscillates. The sphere may be assumed to oscillate with simple harmonic motion.
- (a)State what is meant by simple harmonic motion.[2]
- (b)The variation of the velocity v of sphere P with the displacement x from its mean position is shown in Fig. 3.2. [Figure 3.2]. Use Fig. 3.2 to determine the frequency f of the oscillations of sphere P.[3]
- (c)The period T of the oscillations of sphere P is given by the expression T = 2π√(L/g) where g is the acceleration of free fall. Use your answer in (b) to determine the length L.[2]
- (d)Another pendulum consists of a sphere Q suspended by a thread. Spheres P and Q are identical. The thread attached to sphere Q is longer than the thread attached to sphere P. Sphere Q is displaced and then released. The oscillations of sphere Q have the same amplitude as the oscillations of sphere P. On Fig. 3.2, sketch the variation of the velocity v with displacement x for sphere Q.[2]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [B1] acceleration (directly) proportional to displacement
- [B1] acceleration in opposite direction to displacement / acceleration (directed) towards equilibrium position
- [C1] v = ω(x₀² – x²)½ and ω = 2πf / V₀ = x₀ω and ω = 2πf
- [C1] substitution of any correct point from graph, e.g. for x = 0: 0.25 = 2πf x 8.8 × 10⁻²
- [A1] f = 0.45 Hz
- [C1] 1/0.45 = 2π × (L/9.81)½
- [A1] L = 1.2 m
- [B1] ellipse about the origin with same intercepts on x-axis
- [B1] ellipse about the origin crossing v-axis inside original loop
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