The overall stopping distance of a cyclist is made up of two parts, as shown in Fig. 12.1: • the distance the cyclist travels during the reaction time of the cyclist (the thinking distance) • the distance the cyclist travels after the brakes are applied (the braking distance) [Figure 12.1 (not to scale)]
- (a)State the energy change that occurs during braking.[2]
- (b)(i)A ball rolls in front of a cyclist at time t = 0 and the cyclist brakes and comes to rest. Fig. 12.2 shows the speed-time graph for the cyclist. [Figure 12.2] Using Fig. 12.2, determine the reaction time of the cyclist.[1]
- (b)(ii)Using Fig. 12.2, calculate the thinking distance.[2]
- (b)(iii)State how the braking distance is found using Fig. 12.2.[1]
- (b)(iv)On another occasion, the same cyclist travels at an initial speed of 5.0m/s. A ball rolls in front of the cycle at time t = 0. The cyclist has the same reaction time and the deceleration of the cycle is the same as in Fig. 12.2. On Fig. 12.2 draw the new speed-time graph for the cyclist.[2]
- (b)(v)The braking distance is longer when the cyclist stops on a wet road. Explain why.[3]
- (c)(i)Fig. 12.3 shows the hydraulic braking system of the cycle. [Figure 12.3 (not to scale)] The cyclist applies a force on the brake lever. This increases the pressure in the oil by 1.2 x 10⁶ Pa. The cross-sectional area of piston R is 5.0 × 10⁻⁵ m². Calculate the force F applied by the brake lever to piston R.[2]
- (c)(ii)The force applied to each of the brake pads is larger than F. Explain why.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2016). The mark or mark type is shown in brackets.
- [B1] kinetic energy at start
- [B1] thermal energy/heat energy/ internal energy at end
- [B1] 0.4(0) s
- [C1] (d=) s x t numerical or algebraic
- [A1] 2.8 m
- [B1] area under graph (between 0.4 and 2.4 s) or time (difference) × average speed or ½ x time (difference) × initial speed
- [B1] horizontal line from (0,5) to (0.4,5)
- [B1] line showing braking with same gradient as original line
- [B1] less friction
- [B1] less deceleration or graph less steep or less force backwards/less force opposing motion or same KE lost/work done by friction
- [B1] longer time to stop or larger area under (speed-time) graph or work = force x distance applied correctly
- [C1] (F=) P × A numerical or algebraic
- [A1] 60 N
- [B1] same pressure
- [B1] larger area (of S/brake pads)
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