Table 9.1 shows the melting points and relative electrical conductivities of three elements. Table 9.1 | | carbon (graphite) | magnesium | phosphorus |---|---|---|--- | melting point /°C | 3652 | 649 | 44 | relative electrical conductivity of solid | good | good | poor Use ideas about structure and bonding to explain:
- (a)(i)the difference in the melting points of magnesium and phosphorus[3]
- (a)(ii)the difference in the electrical conductivities of graphite and phosphorus.[2]
- (b)Diamond and graphite are different forms of carbon. Explain, in terms of its structure and bonding, why diamond is used in cutting tools.[2]
- (c)A compound of phosphorus, oxygen and chlorine contains 20.2% phosphorus, 10.4% oxygen and 69.4% chlorine by mass. Deduce the empirical formula of this compound. empirical formula[2]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.
- [1] (a)(i) magnesium (has a high melting point because) has a giant metallic lattice and sea of delocalised electrons
- [1] (a)(i) strong bonding between the ions and delocalised electrons / strong bonding between ions and 'sea' of electrons
- [1] (a)(i) phosphorus (has a low melting point because) there are weak forces between the molecules / phosphorus has weak intermolecular forces
- [1] (a)(ii) graphite has (delocalised) mobile electrons / (delocalised) electrons which can move
- [1] (a)(ii) phosphorus has no mobile electrons / charge carriers
- [1] (b) M1 diamond has a giant structure of covalent bonds
- [1] (b) M2 diamond has strong bonding between all the atoms
- [1] (c) division by correct relative atomic mass e.g. P = 20.2/31, O = 10.4/16, Cl = 69.4/35.5
- [1] (c) division by lowest value to get correct answer of POCl₃
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