The equation for the reaction between calcium carbonate and hydrochloric acid is shown. CaCO3(s) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g) How many moles of calcium carbonate will give 24 cm³ of carbon dioxide when reacted with an excess of the acid? (Assume one mole of carbon dioxide occupies 24 dm³.)
✓ Correct answer
D: 0.001 mol
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