Express the equation tan(θ+ 60°) = 2 + tan(60° – θ) as a quadratic equation in tan θ, and hence solve the equation for 0° ≤ θ ≤ 180°.
- (a)Express the equation tan(θ+ 60°) = 2 + tan(60° – θ) as a quadratic equation in tan θ, and hence solve the equation for 0° ≤ θ ≤ 180°.[6]
Mark scheme
Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.
- [M1] Use tan (A + B) formula and obtain an equation in tan θ
- [A1] Using tan 60° = √3, obtain a horizontal equation in tan θ in any correct form
- [A1] Reduce the equation to 3 tan² θ + 4 tan θ – 1 = 0, or equivalent
- [M1] Solve a 3-term quadratic for tan θ
- [A1] Obtain a correct answer, e.g. 12.1°
- [A1] Obtain a second correct answer, e.g. 122.9°, and no others in the given interval
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →