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A-LevelMathematicsTrigonometry9709/22 · May/June 2020 · Q810 Marks

Show that 3 sin 2θ cot θ = 6 cos² θ.

  1. (a)Show that 3 sin 2θ cot θ = 6 cos² θ.[2]
  2. (b)Solve the equation 3 sin 2θ cot θ = 5 for 0 < θ < π.[3]
  3. (c)Find the exact value of ∫[from π/4 to π/2] 3 sin x cot (1/2)x dx.[5]

Mark scheme

Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.

  1. [B1] Use at least one of sin 2θ = 2 sin θ cos θ and cot θ = cos θ / sin θ
  2. [B1] Use both and conclude 6cos² θ AG
  3. [M1] Attempt solution of cos² θ = 5/6 to find at least one value
  4. [A1] Obtain 0.421
  5. [A1] Obtain 2.72
  6. [M1] Express integrand in form a + b cos x
  7. [A1] Obtain correct integrand 3 + 3 cos x
  8. [*M1] Integrate to obtain px + q sin x
  9. [DM1] Apply limits correctly
  10. [A1] Obtain 3/4π + 3 - 3/√2 or exact equivalent

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About this question

Topic
Trigonometry, A-Level Mathematics (syllabus 9709). Structured question, 10 marks.
Source
A-Level Mathematics, May/June 2020 Paper 2 Variant 2, question 8.

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